Refer to the exhibit.
Given alpha=0.02, which conclusion is justified regarding percentage of body fat, comparing small (S), medium (M), and large (L) wrist sizes?
A. Medium wrist size is significantly different than small wrist size.
B. Large wrist size is significantly different than medium wrist size.
C. Large wrist size is significantly different than small wrist size.
D. There is no significant difference due to wrist size.
Refer to the exhibit.
Based on the control plot, which conclusion is justified regarding the means of the response?
A. All groups are significantly different from each other.
B. 2XL is significantly different from all other groups.
C. Only XL and 2XL are not significantly different from each other.
D. No groups are significantly different from each other.
Customers were surveyed to assess their intent to purchase a product. An analyst divided the customers into groups defined by the company's pre-assigned market segments and tested for difference in the customers' average intent to purchase. The following is the output from the GLM procedure:
What percentage of customers' intent to purchase is explained by market segment? Click the calculator button to display a calculator if needed.
A. <0.01%
B. 35%
C. 65%
D. 76%
A company has branch offices in eight regions. Customers within each region are classified as either "High Value" or "Medium Value" and are coded using the variable name VALUE. In the last year, the total amount of purchases per customer is used as the response variable.
Suppose there is a significant interaction between REGION and VALUE. What can you conclude?
A. More high value customers are found in some regions than others.
B. The difference between average purchases for medium and high value customers depends on the region.
C. Regions with higher average purchases have more high value customers.
D. Regions with higher average purchases have more medium value customers.
This question will ask you to provide a missing option.
Complete the following syntax to test the homogeneity of variance assumption in the GLM procedure:
means Region /
A. test
B. adjust
C. var
D. hovtest
What is a drawback to performing data cleansing (imputation, transformations, etc.) on raw data prior to partitioning the data for honest assessment as opposed to performing the data cleansing after partitioning the data?
A. It violates assumptions of the model.
B. It requires extra computational effort and time.
C. It omits the training (and test) data sets from the benefits of the cleansing methods.
D. There is no ability to compare the effectiveness of different cleansing methods.
An analyst has a sufficient volume of data to perform a 3-way partition of the data into training, validation, and test sets to perform honest assessment during the model building process. What is the purpose of the training data set?
A. To provide an unbiased measure of assessment for the final model.
B. To compare models and select and fine-tune the final model.
C. To reduce total sample size to make computations more efficient.
D. To build the predictive models.
Refer to the confusion matrix:
Calculate the sensitivity. (0 - negative outcome, 1 - positive outcome)
Click the calculator button to display a calculator if needed.
A. 25/48
B. 58/102
C. 25/B9
D. 58/81
The total modeling data has been split into training, validation, and test data. What is the best data to use for model assessment?
A. Training data
B. Total data
C. Test data
D. Validation data
This question will ask you to provide missing code segments.
A logistic regression model was fit on a data set where 40% of the outcomes were events (TARGET=1) and 60% were non-events (TARGET=0). The analyst knows that the population where the model will be deployed has 5% events and
95% non-events. The analyst also knows that the company's profit margin for correctly targeted events is nine times higher than the company's loss for incorrectly targeted non-event.
Given the following SAS program:
What X and Y values should be added to the program to correctly score the data?
A. X=40, Y=10
B. X=.05, Y=10
C. X=.05, Y=.40
D. X=.10, Y=05
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