Admission Tests Admission Tests Certifications GMAT-QUANTITIVE Questions & Answers

• Question 411:

  The remainder when dividing the expression (X + Y) by 5 is 4.

  The remainder of X divided by 10 is 2. What is the remainder of Y divided by 5?

  A. 1.

  B. 2.

  C. 3.

  D. 4.

  E. 5.

  Correct Answer: B

  Plug in numbers that fit the conditions. (X+Y) = 19 and so 19/5 gives a remainder of 4. X = 12 and so 12/10 gives a remainder of 2. Therefore Y is 7. 7/5 = 1. The remainder is 2.

• Question 412:

  Q is a prime number larger than 10. What is the smallest positive number (except 1) that 3Q can be equally divided by?

  A. 3Q.

  B. Q

  C. 3

  D. Q+3

  E. 2Q

  Correct Answer: C

  3Q is a prime number so it can be divide equally by 3Q, by 1 and by the components 3 and Q. The smallest number is 3.

• Question 413:

  A can be divided by 11 with no remainder. Which of the following expressions could be divided by 11 leaving a remainder of 1?

  A. A-20.

  B. A-12.

  C. A-9.

  D. A-10.

  E. A-13.

  Correct Answer: D

  A/11=X, so A=11X. Now change A in answer D with 11X to get: 11X-10. Plug in numbers in X to find out if

  it could leave a remainder of 1 when divided by 11.

  Let's try X=2 and A = 22. In expression D: 22-10=12.

  12/11 = 1 with a remainder of 1. try plugging the same number (2) to each of the expressions to find the

  right answer.

• Question 414:

  The number of bunnies in Peter's yard increases by 4 times every week. How many weeks will it take for the number of bunnies to be divisible by 8 assuming that he started out with 3 bunnies?

  A. 1.

  B. 2.

  C. 3.

  D. 4.

  E. Never.

  Correct Answer: B

  In the beginning he has 3, one week later he has12 and two weeks later he has 48 and that can be equally divided by 8.

• Question 415:

  If X = 23 x 52 x 7, then the expression X/8 is not divisible by:

  A. 1.

  B. 2.

  C. 5.

  D. 7.

  E. 25.

  Correct Answer: B

  From the given expression we learn that X/8 = 25 x 7, which is not divisible by 2.

• Question 416:

  In orange county one fifth of the people are gathering mushrooms and one seventh of the people are collecting apples. What can be the number of people in Orange County?

  A. 60.

  B. 42.

  C. 85.

  D. 140.

  E. 252.

  Correct Answer: D

  The answer must be a number that is divisible by both seven and four. The only possible number is 140.

• Question 417:

  Danny can divide his herd into 5 equal parts and also to 6 equal parts, but not to 9 equal parts. What could be the number of cows Danny has in his herd?

  A. 155.

  B. 336.

  C. 180.

  D. 120.

  E. 456

  Correct Answer: A

  The number of cows is divisible by 5 and 6 but not by 9. Meaning it must end with a 5 or a 0 and be divisible by 3 (the sum of its digits is divisible by 3). That leaves answers C and A only. However, 180 is also divisible by 9 and is ruled out.

• Question 418:

  A and B are integers. The expression (A+1)(B+1) is even.

  What can be said about A and B?

  A. They are both even numbers.

  B. At least one of them is even.

  C. At least one of them is odd.

  D. They are both odd.

  E. Nothing can be said surly on A and B.

  Correct Answer: C

  Because the given expression is even, at least one of the phrases in one of the parenthesis must be even therefore either A or B must be odd.

• Question 419:

  In a recent survey, Q people were asked whether they eat after 22:00 O'clock. 25 percent of the people answered positively and 40 percent of the rest were asked, at what time do they get up in the morning. Which of the following expressions represents the number of people who do not eat after 22:00 and were not asked about the time they get up in the morning?

  A. 3Q/20.

  B. Q/10.

  C. 5Q/9.

  D. 3Q/10.

  E. 9Q/20.

  Correct Answer: E

  75Q/100 is the number of people who eat after 22:00. 60% of that number is the number of people who

  weren't asked upon, when do they get up at the morning.

  60 x (75Q/100) / 100 = 45Q/100 = 9Q/20.

• Question 420:

  A certain factory produces buttons and buckles at a uniform weight. If the total weight of 2 buttons and 2 buckles is one third of 11 buckles and 3 buttons, then the weight of 3 buttons and 2 buckles is how many times that of 5 buckles and 6 buttons?

  A. 7/15.

  B. 4/9.

  C. 6/11.

  D. 5/9.

  E. 8/15.

  Correct Answer: A

  Define B as the weight of a button and K as the weight of a buckle. The total weight of (2B + 2K) is equal to

  (11K + 3B) ---> 3B = 5K B = 5K/3. The question requires the ratio between (3B + 2K) and (5K + 6B).

  The first factor is equal to (5K + 2K = 7K).

  The second factor is equal to (5K + 2(5K)) = (15K).

  The ratio between them is 7:15 and therefore the first factor is 7/15 of the second one.