Admission Tests Admission Tests Certifications GMAT-QUANTITIVE Questions & Answers

• Question 601:

  In a rectangular axis system, what is the distance between the following points: A(3,2) and B(7,5) ?

  A. 5.

  B. 7.

  C. 6.

  D. 4.

  E. 3.

  Correct Answer: A

  First, draw a rectangular axis system and mark the two points. The easiest way to find the distance between them is to draw a triangle, where the line AB is the hypotenuse. You can see that the length of one side of the triangle is (5-2=3) and the other side is (7-3=4). The length of the line AB is received with the help Of the Pythagoras principle: = 5.

• Question 602:

  A, B, C, D and E are 5 consecutive points on a straight line. If BC = 2CD, DE = 4, AB = 5 and AC = 11, what is the length of AE?

  A. 21.

  B. 26.

  C. 30.

  D. 18.

  E. 16.

  Correct Answer: D

  First, draw the line and the points.

  In order to find the length of AE, find the length of CD and BC first.

  BC = AC -AB = 11 -5 = 6.

  BC = 2CD CD = 3.

  AE = 5 + 6 + 3 + 4 = 18.

• Question 603:

  A and B are two circles. The radius of A is twice as large as the diameter of B. What is the ratio between the areas of the circles?

  A. 1:8.

  B. 1:2.

  C. 1:4.

  D. 1:16.

  E. 1:6.

  Correct Answer: D

  The radius of circle A is 4 times larger than the radius of circle B. The area of a circle is a function of the radius squared, therefore the area of radius A is 16 times bigger.

• Question 604:

  To which of the following shapes the area can't be calculated if the perimeter is given?

  A. Circle.

  B. An isosceles right triangle.

  C. Rectangle.

  D. A regular Hexagon.

  E. Square.

  Correct Answer: C

  The perimeter of a rectangle is 2a + 2b. In order to calculate the area we need to know the multiplication of a x b.

• Question 605:

  In a triangle, one side is 6 Cm and another side is 9 Cm. which of the following can be the perimeter of the triangle?

  A. 18.

  B. 25.

  C. 30.

  D. 32.

  E. 34.

  Correct Answer: B

  The third side of the triangle is larger than 3 (The difference between the other two) and smaller than 15

  (The sum of the other two).

  The perimeter is between (6+9+3 = 18) and (6+9+15 = 30). The only answer that is in this range is B.

• Question 606:

  Alfa, Beta and Gamma are inner angles in a triangle. If Alfa = Beta + Gamma, what can't be the size of Beta?

  A. 44 degrees.

  B. 45 degrees.

  C. 89 degrees.

  D. 90 degrees.

  E. There isn't enough data to determine.

  Correct Answer: D

  If Beta is 90 degrees than Alfa is bigger than 90 and the sum of the angles in the triangle will be bigger than 180 degrees.

• Question 607:

  An Ameba is an organic life form that divides into two Amebas each round hour. If at a certain round hour, two Amebas were placed in a jar, how many Amebas will be in the jar in N hours?

  A. 2N

  B. 22N

  C. 2N+1

  D. 2N-1

  E. 2N

  Correct Answer: C

  Let's find the number of Amebas in the first hours. After one hour (N=1) there will be 4 Amebas. After two hours (N=2) there will be 8 Amebas. After three hours (N=3) there will be 16 amebas. Therefore the formula that fits this series is 2N+1.

• Question 608:

  The value of an "Aerosoul" stock changes according to the following method:

  At the end of each month her value is doubled but due to commission the stock's value is decreases by $10. If the value at the beginning of January is $A, what would be her value at the end of February?

  A. 4A ?10.

  B. 4A ?20.

  C. 4A ?30.

  D. 4A ?40.

  E. 4A ?50.

  Correct Answer: C

  At the end of January her value is 2A ?10.

  At the end of February her value is (2 x (2A -10) ?10 = 4A -30).

• Question 609:

  What is the sum of all the even numbers bigger than (-10) and smaller than 12?

  A. 2.

  B. 10.

  C. 0.

  D. 8.

  E. 4.

  Correct Answer: B

  This is a series of numbers with a constant spacing between them. The first number is (-8) and the last is (10), there are 10 numbers altogether. The formula for such a series is: ((-8 + 10) x 10)/2 = 10. The second way to answer such a question is to write the numbers and add them.

• Question 610:

  Chandler is building a fence in the following method: He grounds 10 poles, each 10 Cm thick, in 1 meter

  spaces from each other. He then connects the poles with a barbed wire.

  What is the total length of the fence?

  A. 11.

  B. 12.

  C. 9.9.

  D. 10.

  E. 13.

  Correct Answer: D

  The total width of the poles is (10 x 0.1 = 1) meter. There are 9 spaces between the poles, each 1 meter,

  so it's another 9 meters.

  The total length is (1 + 9 = 10) meters.