A Developer wrote the following code to test a sum3 function that takes in an array of numbers and returns the sum of the first three number in the array, The test passes:
Let res = sum2([1, 2, 3 ]) ;
console.assert(res ===6 );
Res = sum3([ 1, 2, 3, 4]);
console.assert(res=== 6);
A different developer made changes to the behavior of sum3 to instead sum all of the numbers present in the array. The test passes:
Which two results occur when running the test on the updated sum3function?
Choose 2 answers
A. The line 02 assertion passes.
B. The line 02 assertion fails
C. The line 05 assertion passes.
D. The line 05 assertion fails.
Which three options show valid methods for creating a fat arrow function? Choose 3 answers
A. x => ( console.log(` executed ') ; )
B. [ ] => ( console.log(` executed ') ;)
C. ( ) => ( console.log(` executed ') ;)
D. X,y,z => ( console.log(` executed ') ;)
E. (x,y,z) => ( console.log(` executed ') ;)
Refer to the code below:
let timeFunction =() => {
console.log(`Timer called.");
};
let timerId = setTimeout (timedFunction, 1000);
Which statement allows a developer to cancel the scheduled timed function?
A. removeTimeout(timedFunction);
B. removeTimeout(timerId);
C. clearTimeout(timerId);
D. clearTimeout(timedFunction);
A developer has two ways to write a function:
Option A:
function Monster() {
This.growl = () => {
Console.log ("Grr!");
}
}
Option B:
function Monster() {};
Monster.prototype.growl =() => {
console.log("Grr!");
}
After deciding on an option, the developer creates 1000 monster objects.
How many growl methods are created with Option A Option B?
A. 1 growl method is created for Option A.1000 growl methods are created for Option B.
B. 1000 growl method is created for Option A. 1 growl methods are created for Option B.
C. 1000 growl methods are created regardless of which option is used.
D. 1 growl method is created regardless of which option is used.
developer publishes a new version of a package with new features that do not break backward compatibility. The previous version number was 1.1.3. Following semantic versioning format, what should the new package version number be?
A. 2.0.0
B. 1.2.3
C. 1.1.4
D. 1.2.0
A developer writes the code below to return a message to a user attempting to register a new username. If the username is available, a variable named nag is declared and assigned a value on line 03.
What is the value of msg when getAvailableabilityMessage ("newUserName") is executed and get Availability ("newUserName") returns true?
A. "msg is not defined"
B. "newUserName"
C. "User-name available"
D. undefined
Which code change should be done for the console to log the following when 'Click me!' is clicked'
> Row log > Table log
A. Remove lines 13and 14
B. Change line 10 to event.stopPropagation (false) ;
C. Change line 14 to elem.addEventListener ('click', printMessage, true);
D. Remove line 10
Refer to the code snippet:
Function getAvailabilityMessage(item) {
If (getAvailability(item)){
Var msg ="Username available";
}
Return msg;
}
A developer writes this code to return a message to user attempting to register a new username. If the username is available, variable.
What is the return value of msg hen getAvailabilityMessage ("newUserName" ) is
executed and getAvailability("newUserName") returns false?
A. "Username available"
B. "newUserName"
C. "Msg is not defined"
D. undefined
Refer of the string below:
Const str = `sa;esforce'=;
Which two statement result in the word 'Sale'?
Choose 2 answers
A. str, substring (0,5) ;
B. str, substr(0,5) ;
C. str, substring(1,5);
D. str, substr(1,5) ;
A developer has the following array of hourlywages:
Let arr = (8, 5, 9, 75, 11, 25, 7, 75, , 13, 25);
For workers making less than $10 an hour rate should be multiple by 1.25 and returned in a new array.
How should the developer implement the request?
A. let arrl = arr.filter((val) => val < 10).map((num) -> num = 1.25);
B. let arrl = arr .rr.acArray ((val) => ( val < 10 )) ,map((num) => { num * 1.25 ));
C. let arrl = arr-map((num) => { return ran * 1.25 }).filter((val) -> { return val < 10));
D. let arrl = arr.filterBy((val) => val < 10 ).aapBy<(num) -> num = ..25 );
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